Given:
The equation is:
It cuts the x-axis and y- axis at the point A and B respectively.
The area of ∆AOB =12 sq.units.
To find:
The value of <em>k</em>.
Solution:
We have,
Substituting to find the y-intercept.
Substituting to find the x-intercept.
Area of a triangle is:
The height of the ∆AOB is because distance cannot be negative and the base of the ∆AOB is . So, the area of the ∆AOB is:
It is given that, the area of ∆AOB = 12 sq.units.
Therefore, the value of k is either 24 or -24.