<img src="https://tex.z-dn.net/?f=615%20%7B1631%7D%5E%7B2%7D%20" id="TexFormula1" title="615 {1631}^{2} " alt="615 {1631}^{2} "

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snow_tiger [21]

3 years ago

align="absmiddle" class="latex-formula">
what will be the answer

Mathematics

2 answers:

Lisa [10]3 years ago

8 0

Answer:

37,842,563,960,161

Step-by-step explanation:

The squared symbol means to multiply the same number twice,

so:

6,151,631 × 6,151,631 = 37,842,563,960,161

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Have a great summer :)

Bogdan [553]3 years ago

5 0

Answer above is correct

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Dinosaurs have been extinct for about 6.5×10 exponent seven years while Neanderthals have been extinct for about 3.0×10 exponent

shutvik [7]

Answer:

6.49 × 10⁷ years

Step-by-step explanation:

For Dinosaurs

Dinosaurs have been extinct for about 6.5×10 exponent seven years

6.5 × 10⁷ years

For Neanderthals

Neanderthals have been extinct for about 3.0×10 exponent four years

= 3.0 × 10⁴ years

How many longer is calculated by Subtraction

6.5 × 10⁷ years - 3.0 × 10⁴

= 64970000 years

= 6.49 × 10⁷ years

5 0

3 years ago

Pls help i need this to get my grade up

vekshin1

Answer:

Step-by-step explanation:

So first I solved for y. The angle boc and cod together have to be 180 degrees so I subtracted 180 from 45 and then divided by 5. I got 27. Then since I knew what y was I could solve x. Since 5 times 27 is 135. I just plugged in 22 and 23 and realized it had to be 22.

RAISE THAT GRADE!! you got this I hope this helps!

4 0

3 years ago

Read 2 more answers

Pls help me with this

grin007 [14]

Answer:

k=8

Step-by-step explanation:

divide both sides by 11 to get nine

then subtract 1 from both sides to get

7 0

3 years ago

A set of city temperatures in April are normally distributed with a mean of 19.7 degrees Celsius and a standard deviation of 2 d

Sati [7]

Answer:

19.77% of average city temperatures are higher than that of Cairo

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 19.7, \sigma = 2$