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DerKrebs [107]
3 years ago
6

Y=e^x how do I solve this

Mathematics
1 answer:
kolezko [41]3 years ago
6 0
If you're trying to solve for x, keep in mind the ln (natural log) of e is 1. So take the natural log of both sides, which will give you ln Y = ln e^x. The ln and e essentially cancel out, so you're left with x = ln Y. 
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X + 5y = 28 2x + 3y = 21 Solve for x and y.
snow_tiger [21]
First what we gonna do is solve for y.
x+5y=28 Subtract 5y both sides.
  -5y  -5y
x=-5y+28 Then you have to replace x with the equation.
2(-5y+28)+3y=21 Multiply.
-10y+56+3y=21 Combine like terms and subtract 56 both sides. 
       -56        -56
-7y=-35 Divide -7 both sides.
y=5 Simplify.
x=-5(5)+28 Multiply and add.
x=-25+28
x=3
Heres your answer x=3 and y=5.
6 0
3 years ago
What is the value of 7^2 x 7^0
sineoko [7]
The answer is 49

Hope this helps
7 0
2 years ago
Read 2 more answers
Not sure how this works as a fraction to place the dot in the right place
vodomira [7]

Answer:

You would place 7/6 one tick to the right of 1, and -2 5/6 one tick to the right of -3

Step-by-step explanation:

4 0
2 years ago
Is 2.81 an irrational number
nekit [7.7K]

Answer:

No.

Step-by-step explanation:

It can be written as 2 81/100 or 281/100 so it is not irrational. An irrational number is a number that cannot be written as a ratio of two numbers

5 0
2 years ago
Read 2 more answers
Use Cramer's Rule to solve the following system: –2x – 6y = –26 5x + 2y = 13
andriy [413]
\bf \begin{cases}
-2x-6y&=-26\\
\quad 5x+2y&=13
\end{cases}\stackrel{\textit{determinant of the coefficients}}{D=
\begin{bmatrix}
-2&-6\\5&2
\end{bmatrix}}\implies (-4)-(-30)
\\\\\\
D=-4+30\implies \boxed{D=26}\\\\
-------------------------------\\\\

\bf x=\cfrac{D_x}{D}\implies x=\cfrac{
\begin{bmatrix}
\boxed{-26}&-6\\\\ \boxed{13}&2
\end{bmatrix}}{D}\implies x=\cfrac{(-52)-(-78)}{26}
\\\\\\
x=\cfrac{-52+78}{26}\implies x=\cfrac{26}{26}\implies \boxed{x=1}\\\\
-------------------------------\\\\
y=\cfrac{D_y}{D}\implies y=\cfrac{
\begin{bmatrix}
-2&\boxed{-26}\\\\ 5&\boxed{13}
\end{bmatrix}}{D}\implies y=\cfrac{(-26)-(-130)}{26}
\\\\\\
y=\cfrac{-26+130}{26}\implies y=\cfrac{104}{26}\implies \boxed{y=4}
4 0
3 years ago
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