1) Draw the triangles JKL and J'K'L' in a same coordinate system.
When I did that, I realize the if you translate the triangle JKL 1 unit left and then you reflects the image across the x-axys you get the you get the triangle J'K'L'.
So, select the boxes in that same order:
1) translation 1 unit left
2) reflection across the x - axis.
2) The answer ot the second question is line r.
That is called the line of reflection because if you reflect the figures through it you will have the same figure.
<span>y=-40x+100 This equation says your friend lives 100 miles away and travels 40 miles per hour. He takes 2.5 hours to get there.
y = -40x + 100 If y=0 then x = 100/40 = 2.5 hours and if x=0 then y=100.
You are 150 miles away and it takes you 2.5 hours to get there so your equation is:
0 = -2.5v + 150 You are solving for velocity.
v = 150/2.5 = 60 miles per hour. Now we can write the answer to the problem.
y = -60x + 150 Compare that to the original statement.
y = -40x + 100 Your buddy's speed is 40 and yours is 60. He has 100 miles to go and you have 150. Otherwise it's the same equation.</span><span>
</span>
Answer:
209.6
Step-by-step explanation:
Answer:
In bold below.
Step-by-step explanation:
Find derivative which gives the velocity:
V = h' = -32t + 28
At maxm height V = 0 so
-32t + 28 = 0
Time to reach maxm height t = -28/-32 = 0.875 seconds.
So maxm height
= -16(0.875)^2 + 28*0.875 + 8
= 20.25 ft.
