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eduard
3 years ago
13

What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

Given:

The polynomials are:

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

To find:

The completely simplified sum of the polynomials.

Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y

Sum=-2xy^5+3x^4y+3x^2y^2

Therefore, the sum of the given polynomials is -2xy^5+3x^4y+3x^2y^2. It is a polynomial with degree 6 and leading coefficient -2.

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Simplify the expression by combining like terms if possible. If not possible select already simplified. 4a^2+2a+4a^2-5
vichka [17]
So the expression is: 4 a^{2} + 2a + 4 a^{2} - 5

You can combine like terms, which are terms that contain the same variables raised to the same power. That means you can combine the two 4 a^{2}. 4 a^{2} + 4 a^{2} = 8 a^{2} The other terms can't be combined.

Your final answer should be 8 a^{2} +2a-5.
8 0
3 years ago
The 12th term and the sim of 1+3+5+7+.....
zzz [600]

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term


7 0
4 years ago
Anyone want to help me with math
Xelga [282]

Ok, I am ready, what are the questions.

Tell me in the comment section

6 0
3 years ago
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