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2 years ago

14

The equation P = 6s represents the perimeter P of a regular hexagon with side length s. What is the perimeter of a regular hexag

on with side length 7 m?

1 answer:

kozerog [31]2 years ago

4 0

Answer: 42

Step-by-step explanation:

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If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin

kirill115 [55]

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

3 0

2 years ago

The number of books checked out from the library varies directly with the number of book reports assigned. there were 3375 books

yan [13]

3375/225=15
13500/15=900 books
The answer is D

5 0

2 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

2. Sam has two part-time jobs, delivering pizza and mowing lawns. He makes $9/hr delivering pizza and $7/hr mowing lawns. Last w

frutty [35]

Answer:

<h2>22 hours and 10 hours </h2>

Step-by-step explanation:

let the jobs be x and y, so that

x+y=32--------1

9x+7y=248----2

x=32-y

substitute x=32-y for x in equation 2 we have

9(32-y)+7y=248

open bracket we have

288-9y+7y=248

-2y=248-288

-2y=-40

2y=40

divide both sides by 2 we have

y=40/2

y= 10 hours

subtitute y=10 for y in equation 1 to find x

x+10=32--------1

x=32-10

x=22

x=22 hours

4 0

3 years ago

What is (9,+9)0-2 and 158932x738995

Mekhanik [1.2K]

Answer:

117,449,953,338.

Step-by-step explanation:

(9,+9)0-2 = 0 - 2

= -2.

158932 x 738995

= 117,449,953,340

So the answer is

117,449,953,340 - 2

= 117,449,953,338.

6 0

3 years ago