Answer:
C. H(x) = 2x+6
Step-by-step explanation:
Volume of the cylindrical silo = Area of its circular base × Height
Volume of the cylindrical silo = πr²×H
If the area of the circular base of the silo is given by the function A(x), the volume is given by C(x) and the height is given by H(x), the formula can be expressed as;
C(x) = A(x) × H(x)
The height of the cylindrical silo will be;
H(x) = C(x)/A(x)
Given C(x) = 6.28x³ + 18.84x² and
A(x) = 3.14x²
H(x) = 6.28x³ + 18.84x²/3.14x²
H(x) = x²(6.28x+18.84)/3.14x²
H(x) = (6.28x+18.84)/3.14
H(x) = 3.14(2x+6)/3.14
H(x) = 2x+6
Hence, the function, H(x) that represents the height of the silo is 2x+6.
Answer:
The measure of angle BCD is 
Step-by-step explanation:
step 1
Find the value of x
we know that
-----> form a straight line
substitute the values
step 2
Find the measure of angle BCD
substitute the value of x
Answer:
6
Step-by-step explanation:
Answer:
i think its B or C most likely C
Step-by-step explanation:
Answer:
3.24 × 10 ^ -5
Step-by-step explanation:
3.24 × 10 ^ -5 is already a standard form...
