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Triss [41]
3 years ago
9

In the figure AB is parallel to CD. BC is parallel to AE. angle ABD measures (3x+4). angle BCD measures (6x-8). angle EDF measur

es (7x-20). what is the degree measure of angle BCD?
Guys I really need ur help. my test is tomorrow and I've been stuck on this question since yesterday. I literally am about to have a mental breakdown
​

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer:

The measure of angle BCD is 68.5\°

Step-by-step explanation:

step 1

Find the value of x

we know that

m -----> form a straight line

substitute the values

(3x+4)\°+(6x-8)\°+(7x-20)\°=180\°

(16x-24)\°=180\°

16x=180\°+24\°

16x=204\°

x=12.75\°

step 2

Find the measure of angle BCD

m

substitute the value of x

m

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100 points!! Brainliest if correct!!
Elena-2011 [213]

surface area (S) of a right rectangular solid is:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

W = width

H = height

-----

you have:

L = 7

W = a

H = 4

-----

formula becomes:

S = 2*7*a + 2*7*4 + 2*a*4

simplify:

S = 14*a + 56 + 8*a

combine like terms:

S = 22*a + 56

-----

answer is:

S = 22*a + 56 (equation 2)

-----

to prove, substitute any value for a in equation 2:

let a = 15

S = 22*a + 56 (equation 2)

S = 22*15 + 56

S = 330 + 56

S = 386

-----

since a = 15, then W = 15 because W = a

go back to equation 1 and substitute 15 for W:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

W = width

H = height

-----

you have:

L = 7

W = 15

H = 4

-----

equation 1 becomes:

S = 2*7*15 + 2*7*4 + 2*15*4

perform indicated operations:

S = 210 + 56 + 120

S = 386

-----

surface area is the same using both equations so:

equations are good.

formula for surface area of right rectangle in terms of a is:

S = 22*a + 56

-----

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