Answer:
option A
Step-by-step explanation:
Answer:
The correct answer is multiply the first equation by -2.
Step-by-step explanation:
The reason for this is then you'd be left with the following two equations.
-6x - y = -6
6x - y = 2
If you add these two together you would cancel out the x terms.
The value of diameter and radius of circle is 7 cm and 3.5cm.
According to the statement
we have given that the a figure of circle and we have to find the radius and the diameter of the circle.
So, We know that the
The radius of a circle runs from its center to its edge, the diameter runs from edge to edge and cuts through the center.
Here from the figure it is clear that the
Diameter of circle = 7cm
and the radius of circle we have to find
So,
Radius of circle = Diameter /2
Substitute the values in it then
Radius of circle = 7cm /2
Radius of circle = 3.5 cm.
So, The value of diameter and radius of circle is 7 cm and 3.5cm.
Learn more about the diameter and radius of circle here
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Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;
- 1. Arcs are drawn to cross the given line twice on either side relative to the point
- 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line
Description:
1. One of the first steps is to place the compass on the point and from
point, draw arcs to intersect or cross the given line at two points.
2. The compass is placed at each of the intersection point in step 1 and
(opened a little wider when constructing from a point on the line) arcs are
drawn on one (the other side of the point off the line) side of the line with
the same opening (radius) of the compass to intersect each other.
3. From the point of intersection of the arcs in step 2, a line is drawn with a
straight edge passing through the given point.
Learn more about perpendicular lines here:
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This question can’t be answered unless you give what the coordinates of Q15 are.