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3 years ago

12

What is the relationship between the two quantities in the table?

2 answers:

sertanlavr [38]3 years ago

8 0

The answer is 10 because it all goes up by 10

viktelen [127]3 years ago

4 0

Answer:

The relationship between the quantities is “+ 9.” because if you trust me then you will get it right

Step-by-step explanation:

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Does a negative plus a negative plus a negative plus a negative plus a negative equal a positive

ra1l [238]

No thats only if your multiplying it gets confusing like that

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4 years ago

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three ounces of cinnamon cost $2.40. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound?

tatiyna

Answer:
One pound equals $38.4
Step-by-step explanation:
Times the ounces by the cost

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3 years ago

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Which of the following is a monomial A. 12c B. C^2 -16 C. c^2+c+6 D. C^3 +4c^2 -12c + 7

abruzzese [7]

Answer is A. 12c
A monomial only consists of one term (12c),
Binomials consist of two terms (c^2 - 16)
Trinomials consist of three terms (c^2 + c + 6)

An easy way of remembering which is which is to look at the prefixes.
Mono= 1
Bi= 2
Tri= 3

8 0

3 years ago

The Women's Club has sold 180 of the 360 circus tickets they need to sell. What fraction has been sold?

lukranit [14]

180/360

divide 180 top and bottom

180/180 = 1
360/180 = 2

1/2 sold is your answer

hope this helps

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3 years ago

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Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10

Iteru [2.4K]

Answer:

The number of bacteria $B$ after $d$ days is given by

$B = B_0 (3)^{\frac{1}{10} d}$

where $B_0$ is the initial number of bacteria.

Step-by-step explanation:

The number of bacteria $B$ in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

$B = B_0 *3,$

where $B_0$ is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

$B = (B_0 *3)*3$

after the 3rd day,

$B =( B_0 *3*3)*3$

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

$B = B_0 (3)^n$

where $n$ is is the <em>n</em>th 10-days.

Since, $n$ is 10 days, we have

$d =10n$

or

$n =\dfrac{1}{10}$

Substituting that into $B = B_0 (3)^n$ , we get:

$\boxed{ B = B_0 (3)^{\frac{1}{10} d}}$

8 0

3 years ago