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kupik [55]
2 years ago
12

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 6% vinegar, and the second brand co

ntains 11% vinegar. The chef
wants to make 200 milliliters of a dressing that is 9% vinegar. How much of each brand should she use?
Mathematics
1 answer:
Nuetrik [128]2 years ago
7 0

Answer:

The chef will use 120 milliliters of 11% vinegar, and 80 milliliters of 6% vinegar.

Step-by-step explanation:

Since a chef is going to use a mixture of two brands of Italian dressing, and the first brand contains 6% vinegar, and the second brand contains 11% vinegar, and the chef wants to make 200 milliliters of a dressing that is 9% vinegar, to determine how much of each brand should she use the following calculation must be performed:

100 x 0.11 + 0 x 0.06 = 11

90 x 0.11 + 10 x 0.06 = 10.5

80 x 0.11 + 20 x 0.06 = 10

70 x 0.11 + 30 x 0.06 = 9.5

60 x 0.11 + 40 x 0.06 = 9

200 x 0.6 = 120

200 x 0.4 = 80

Thus, the chef will use 120 milliliters of 11% vinegar, and 80 milliliters of 6% vinegar.

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We need to work out the z-value of each question to work out the probability

Question a)

We have
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We want to find the probability of z < -0.77 so we read the z-table for the value of z on the left of -0.77 we have the probability P(z< -0.77) = 0.2206

The table is attached in picture 1 below

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Question b)

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The table reading is shown in the second picture below

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The value of z between 5 minutes and 10 minutes is

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Step-by-step explanation:

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