Answer:
1.) 12000
2.) 6750
3.) 2.41
Step-by-step explanation:
Given the Equation :
f(t)=12,000(3/4)^t. ; where, t = time ; f(t) = worth of car at time, t
When, car was purchased, t = 0
t = 0
f(0) = 12000(3/4)^0
= 12000 * 1
= 12000
2.)
f(2) ; this mean the worth of the car after 2 years :
f(2)=12,000(3/4)^t.
12000(3/4)^2
12000 * 0.5625
= 6750
When car will be worth 6000
f(t) = 6000
f(t)=12,000(3/4)^t.
6000 = 12,000(3/4)^t
6000 / 12000 = (3/4)^t
1/2 = (3/4)^t
Take the log of both sides :
Log(0.5) = log(0.75)^t
log(0.5) = tlog(0.75)
- 0.301029 = - 0.124938t
t = - 0.301029 / - 0.124938
t = 2.4094
t = 2.41 years
Answer:
The answer is 10
Step-by-step explanation:
- 14 -(17 - 5) + 8
- 14 -17 + 5 + 8
- -3 + 13 = 10
- 10 is your answer.
Answer:
10.25
Step-by-step explanation:
Using the pythagorean theorem
13^2 = 8^2 + (ML)^2
169 = 64 + (ML)^2
Subtract 64 from both sides
105 = (ML)^2
Take the square root of both sides
10.25 = ML
Answer:
325
Step-by-step explanation:
Total Tickets = 585
Let the adult tickets be = x
If 65 fewer student tickets were sold than adult tickets then Student tickets = x-65
Student Tickets + Adult Tickets = 585
x + (x-65) = 585
x + x - 65 = 585
2x - 65 = 585
2x = 585 + 65
2x = 650
2x/2 = 650/2
x = 325
Answered by Gauthmath
