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Ierofanga [76]
3 years ago
6

In standerd form what is the answer to y=6x-1 looking for x

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Answer:

x=1/6 or 1.16 (6 repeating) or x=6^-1

Step-by-step explanation:

y=6x-1

substitute y =0

0=6x-1

Move the variable to the left

-6x =-1

Divide on both dies

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Given m
kenny6666 [7]

Answer:

<h2>x = 145°, y = 35°</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

m || n

<em><u>So</u></em><em><u>,</u></em>

35° = y° <em>[</em><em>Alternate</em><em> </em><em>interior</em><em> </em><em>angles</em><em>]</em>

<em>And</em><em>,</em>

y° + x° = 180° <em>[</em><em>Since</em><em> </em><em>linear</em><em> </em><em>pair</em><em>]</em>

=> x + 35 = 180

=> x = 180 - 35

=> x = 145°

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>145</u></em><em><u>°</u></em><em><u>,</u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>35</u></em><em><u>°</u></em>

6 0
3 years ago
Read 2 more answers
Plz I need help ASAP
vekshin1
All I know for sure is that the first one is an inequality
3 0
2 years ago
Find p and q for which the linear eqn has infinite solutions
jekas [21]

Answer:

p= 2.5

q= 7

Step-by-step explanation:

The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.

Equations in slope- intercept form:

6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)

12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒  y=12/(2p-1)x - (5q-1)/(2p-1)

Slopes equal:

6/(2p-3)= 12/(2p-1)

6(2p-1)= 12(2p-3)

12p- 6= 24p - 36

12p= 30

p= 30/12

p= 2.5

y-intercepts equal:

(2q+3)/(2p-3)= (5q-1)/(2p-1)

(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)

(2q+3)/2= (5q-1)/4

4(2q+3)= 2(5q-1)

8q+12= 10q- 2

2q= 14

q= 7

7 0
3 years ago
Solve for z. 8z − 4 = 7z
aleksandr82 [10.1K]

8z − 4 = 7z

move 8z to the other side

sign changes from +8z to -8z

8z-8z-4=7z-8z

-4= 7z-8z

-4= -z

mutiply both sides by -1 to get +z

(-4)(-1)= (-z)(-1)

Answer:

z= 4

5 0
3 years ago
Read 2 more answers
. Find two consecutive odd integers whose product is 99. (Note: There are two different pairs of consecutive odd
Tom [10]

Answer:

9 and 11

Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.

n(n + 2) = 99

Solve for n.

n2 + 2n - 99 = 0

(n + 11)(n - 9) = 0 ⇒

Two solutions:

n = -11

n + 2 = -9

and

n = 9

n + 2 = 11

Test the answers.

4 0
3 years ago
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