Answer:
the g's contributing term for the overall uncertainty of P is ![dP_g = [\frac{dg}{g}]](https://tex.z-dn.net/?f=dP_g%20%3D%20%20%5B%5Cfrac%7Bdg%7D%7Bg%7D%5D)
Step-by-step explanation:
From the question we are told that
The pressure is 
The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation

=>
Then the next step is to differentiate both sides of the equation

=> 
We asked to obtain the contribution of the term g to the uncertainty of P
This can deduced from the above equation as
![dP_g = [\frac{dg}{g}] P](https://tex.z-dn.net/?f=dP_g%20%3D%20%20%5B%5Cfrac%7Bdg%7D%7Bg%7D%5D%20P)
Take your x values in each coordinate and subtract 2, and take your y values and subtract 1.
Q (0-2), (-1-1)
= (-2,-2)
D (-2-2), (2-1)
= (-4, 1)
V (2-2), (4-1)
= (0,3)
J (3-2), (0-1)
= (1,-1)
You can also draw it on a graph and then translate all coordinates 2 units left and 1 down to see the end results.
Answer:
96π^2 = 947.48
Step-by-step explanation:
π × r² × h
8π times 3*4*π