We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
Answer:
B. s = 13753
Step-by-step explanation:
s - 10000 = 3753
To find value of s, add both sides by 10000
s - 10000 = 3753
+10000 +10000
-----------------------------------
s = 13753
Answer:
C
Step-by-step explanation:
time is directly proportional to the number of problems in the set
=> x = ky
k = constant of proportionality
when k = 12
x = 12y
by making y the subject, we divide both sides by 12
=> y = x/12
It would be an average of about 8.00 (7.99 to be somewhat exact). You get this by dividing the total amount by 200, the dividing that by 363.
Answer: 1 1/3
Step-by-step explanation: Hope this helped!
