I think the third option is correct.
Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
-45
Step-by-step explanation:
add 10 to -25, then divide 1/3 to that answer, which is -15. and you get -45
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Step-by-step explanation:
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Answer: 7 3/4
Step-by-step explanation:
3 1/4 + 4 2/4 = 7 3/4