All categories

3 years ago

What is an equation of the line that passes through the points (3, 4) and (-4,-3)?

Mathematics

1 answer:

yan [13]3 years ago

4 0

<h2>Answer: y = x + 1 </h2>

Step-by-step explanation:

For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:

The question gives us two points, (3, 4) and (-4,-3), from which we can find the slope and later the equation of the line.

<u>Finding the Slope</u>

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

= (4 - (- 3)) ÷ (3 - (-4))

= 1

<u>Finding the Equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

⇒ y - (-3) = 1 (x - (-4))

y + 3 = (x + 4)

we could also transform this into the slope-intercept form ( y = mx + c)

since y + 3 = (x + 4)

⇒ y = x + 1

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

You might be interested in

Difference in the following polynomials (6x^3 - 2x^2 + 4)<br> -(2x^3 + 4x^2 - 5)

Colt1911 [192]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{4x^3-6x^2+9}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Find \ Difference: \ \left(6x^3\:-\:2x^2\:+\:4\right)-\left(2x^3\:+\:4x^2\:-\:5\right)}$

$\bold{-----------------------}$

$\bold{Remove \ Parenthesis}$

$\bold{6x^3-2x^2+4-\left(2x^3+4x^2-5\right)}$

$\bold{Remove \ Parenthesis \ / \ Simplify}$

$\bold{-\left(2x^3+4x^2-5\right): \ -2x^3-4x^2+5}$

$\bold{Rewrite}$

$\bold{6x^3-2x^2+4-2x^3-4x^2+5}$

$\bold{[Simplify \ 6x^3-2x^2+4-2x^3-4x^2+5] \ 4x^3-6x^2+9}$

$\bold{4x^3-6x^2+9}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

6 0

4 years ago

100 POINTS TO RIGHT AWNSER!!!!

makvit [3.9K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

——————————

The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

—————

C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

—————

D) r < 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

Now all real numbers are included in the union. So this is the right choice.

Answer: option D) r < 5 or r > – 1.

I hope this helps. =)

6 0

3 years ago

A 2000 lb crystal chandelier in a Las vegas Hotel is suspended by 2 cables.

Musya8 [376]

Answer:

maaf tidak tau ya saya wkwkwk

5 0

3 years ago

In Mr. Jegou's neighborhood 35% of the houses are blue. Write the

ivann1987 [24]

Answer:

Fraction: 3/20

Decimal: 0.35

Step-by-step explanation:

a) 100% - 35% = 65

So, 65% of the houses are NOT blue.

..............................................

Fraction: 3/20

Decimal: 0.35

3 0

3 years ago

Read 2 more answers

Which statement is true for brainliest

alexgriva [62]

Answer:

<A≅<Z

Step-by-step explanation:

Hope This Helps!

6 0

3 years ago