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Greeley [361]
3 years ago
9

What is an equation of the line that passes through the points (3, 4) and (-4,-3)?

Mathematics
1 answer:
yan [13]3 years ago
4 0
<h2>Answer:   y =  x  + 1 </h2>

Step-by-step explanation:  

        For us to write the equation for this line, we need to (1) find the slope of the line, and (2) use one of the points to write an equation:

       The question gives us two points, (3, 4) and (-4,-3), from which we can find the slope and later the equation of the line.

<u>Finding the Slope</u>

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                         =  (4 - (- 3)) ÷ (3 - (-4))  

                                         =   1  

<u>Finding the Equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

                                 ⇒  y - (-3) =  1 (x - (-4))

                                         y + 3 =  (x + 4)

 

we could also transform this into the slope-intercept form ( y = mx + c)

                                    since  y + 3 =  (x + 4)

                                             ⇒     y = x + 1

                                       

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

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Answer:

Option b) is correct.

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Step-by-step explanation:

Given expression is 2x^4-32

To find the completed factor for the given expression:

2x^4-32:

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Now rewritting the above  expression as below

=2(x^4-2^4)  (since 16 can be written as the number 2 to the power of 4)

=2((x^2)^2-(2^2)^2)

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Option b) is correct.

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