1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timama [110]
3 years ago
7

Consider the efficiency of locating the kth element in a singly-linked list. How does that compare to locating the kth element i

n a doubly-linked list
Computers and Technology
1 answer:
eimsori [14]3 years ago
4 0

Answer:

Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list

Explanation:

Assuming that  both lists have firs_t and last_ pointers.

For a singly-linked list ; when locating a kth element, you have iterate through a number of k-1 elements which means that locating an element will be done only in one ( 1 ) direction

For a Doubly-linked list : To locate the Kth element can be done from two ( directions ) i.e. if the Kth element can found either by traversing the number of elements before it or after it . This makes finding the Kth element faster because the shortest route can be taken.

<em>Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list </em>

You might be interested in
The classification of clouds is based on their _____.
goblinko [34]
Clouds might be ordered by shape and by height. Luke Howard, a British drug specialist was the first to portray cloud shapes utilizing Latin terms, for example, cirrus, cumulus or stratus. The division of mists into ten fundamental cloud structures or cloud genera depends on his productions.
5 0
3 years ago
Read 2 more answers
________ involves the use of the internet to steal important information.
Ivenika [448]
Phishing involves the use of the Internet to steal important information.
Shoulder surfing refers to people spying on other people while they are using an ATM. Skimming a credit card refers to thieves using a device in ATMs to steal information from cards. Dumpster diving refers to picking trash from dumpsters.
5 0
3 years ago
How do is excel interpret data?
juin [17]

Explanation:

Once a spreadsheet has a data set stored within its cells, you can process the data. Excel cells can contain functions, formulas and references to other cells that allow you to glean insights in existing data sets, for example by performing calculations on them.

4 0
3 years ago
Write a statement that adds 1 to the variable reverseDrivers if the variable speed is less than 0,adds 1 to the variable parkedD
ch4aika [34]

Answer:

The c++ coding for this scenario is given below.

if( speed < 0 )

       reverseDrivers = reverseDrivers + 1;

   else if( speed >= 0 && speed < 1 )

       parkedDrivers = parkedDrivers + 1;

   else if( speed >= 1 && speed < 40 )

       slowDrivers = slowDrivers + 1;

   else if( speed >= 40 && speed <= 65 )

       safeDrivers = safeDrivers + 1;

   else

       speeders = speeders + 1;

Explanation:

First, five integer variables are declared and initialized.

int reverseDrivers = 0, parkedDrivers = 0, slowDrivers = 0, safeDrivers = 0, speeders = 0;

All the above variables need to be incremented by 1 based on the given condition, hence, these should have some original value.

Another variable speed of data type integer is declared.

int speed;

The variable speed is initialized to any value. User input is not taken for speed since it is not mentioned in the question.

Based on the value of the variable speed, one of the five variables, declared in the beginning, is incremented by 1.

The c++ program to implement the above scenario is as follows.

#include <iostream>

using namespace std;

int main() {

   int reverseDrivers = 0, parkedDrivers = 0, slowDrivers = 0, safeDrivers = 0, speeders = 0;

   int speed = 34;    

   if( speed < 0 )

   {

       reverseDrivers = reverseDrivers + 1;

       cout << " reverseDrivers " << endl;

   }

   else if( speed >= 0 && speed < 1 )

   {

       parkedDrivers = parkedDrivers + 1;

      cout << " parkedDrivers " << endl;

   }

   else if( speed >= 1 && speed < 40 )

   {

       slowDrivers = slowDrivers + 1;

      cout << " slowDrivers " << endl;

   }

   else if( speed >= 40 && speed <= 65 )

   {

       safeDrivers = safeDrivers + 1;

       cout << " safeDrivers " << endl;

   }

   else

   {

       speeders = speeders + 1;

       cout << " speeders " << endl;

   }    

return 0;

}

The program only outputs the variable which is incremented based on the value of the variable speed.

OUTPUT

slowDrivers

3 0
3 years ago
What is a multi-user computer? a computer that has a printer connected to it a computer that is able to access the internet a co
Varvara68 [4.7K]
<span>a computer that is used by more than one employee

A multi-tasking computer is </span><span>able to run more than one program</span>
8 0
3 years ago
Other questions:
  • Write a program to test your functions as follows: Obtain a random number seed from the command line of your program using comma
    10·1 answer
  • Which of the following represents inbound logistics for a bookstore
    13·1 answer
  • In general, font size for software-generated presentation slides should be no smaller than __________ points.
    8·1 answer
  • The architecture in which the database resides on a back-end machine and users access data through their workstations is
    5·2 answers
  • If you want to change the name or file type of an existing word processing document, what command should you use?
    11·2 answers
  • What did Adam and Eve look like?
    7·2 answers
  • I need a explanation for this 02 question for a test I will have .
    11·1 answer
  • Public class Square extends Shape{
    13·1 answer
  • Write a method doubleUp that doubles the size of a list of integers by doubling-up each element in the list. Assume there's enou
    13·1 answer
  • How does social network use message to entertain?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!