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timama [110]
3 years ago
7

Consider the efficiency of locating the kth element in a singly-linked list. How does that compare to locating the kth element i

n a doubly-linked list
Computers and Technology
1 answer:
eimsori [14]3 years ago
4 0

Answer:

Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list

Explanation:

Assuming that  both lists have firs_t and last_ pointers.

For a singly-linked list ; when locating a kth element, you have iterate through a number of k-1 elements which means that locating an element will be done only in one ( 1 ) direction

For a Doubly-linked list : To locate the Kth element can be done from two ( directions ) i.e. if the Kth element can found either by traversing the number of elements before it or after it . This makes finding the Kth element faster because the shortest route can be taken.

<em>Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list </em>

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Zarrin [17]

Answer:

#include <stdio.h>

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printf("\n");

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printf("\n");

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for(int i=1; i<=12; i++)

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if(lowRain>rainfall[i])

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lowRain = rainfall[i];

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Answer:

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