Answer:
The statement in Python is:
print("The average pH of citrus fruits is ",avg_citrus_pH)
Java
System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);
C++
cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;
Explanation:
The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)
Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable
In Python, use print()
In c++, use cout<<
In Java, use System.out.print()
So, the statements are:
Python:
print("The average pH of citrus fruits is ",avg_citrus_pH)
Java
System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);
C++
cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;
Answer:
An error will be occurred here. In C++ a function must be like
returntype function_name(){
}
but the functions in given class does not have returntype given. So there will be a syntax error.
If the returntype is defined then the code does not show any output since nothing is printed in the main function.
You are changing the word
You cant go to a specialist if you cannot figure it out or to someone who knows how to hack because the way iCloud is set up you wont be able to unless you can factory reset it by downloading jail break
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
