(7x3 + 7x2 – 4) + (x3 – 5x2 – 3x + 8)

Mathematics

1 answer:

aksik [14]2 years ago

8 0

Answer:

it's not clear what do you want to with this? it's not even an equation explain your problem so we can solve it

Explain step by step:

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The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is given below, where k is th

andrew11 [14]

The average rate of blood flow is given by

$\displaystyle\frac1{R-0}\int_0^Rv(r)\,\mathrm dr=\frac kR\int_0^R(R^2-r^2)\,\mathrm dr$
$=\dfrac kR\left(R^2r-\dfrac13r^3\right)\bigg|_{r=0}^{r=R}$
$=\dfrac kR\left(R^3-\dfrac13R^3\right)$
$=\dfrac{2kR^2}3$

3 0

2 years ago

Which equation is linear? a xy = 60 b y + 1 = x c 3x – 2y = 5

Firlakuza [10]

Answer:

equation B is linear. A linear equation will not contain exponents.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Help I don't understand this, Can someone explain this to me?

saul85 [17]

Answer:

The second answer is correct (5 x 1,000,000,000)

Step-by-step explanation:

Just count the number of zeros. Multiplying a number liket his by five doesn't change the number of zeros

7 0

2 years ago

Read 2 more answers

10.

frosja888 [35]

$10.62? Im not sure if its correct

8 0

2 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: