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3 years ago

(7x3 + 7x2 – 4) + (x3 – 5x2 – 3x + 8)

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

it's not clear what do you want to with this? it's not even an equation explain your problem so we can solve it

Explain step by step:

You might be interested in

Find the value of x.

Leona [35]

This is an isosceles triangle. Therefore, at the base we have congruent angles (look at the picture).

We have the equation:

(5x + 13)° + (3x + 7)° = 180°

5x + 13 + 3x + 7 = 180 <em>combine like terms</em>

(5x + 3x) + (13 + 7) = 180

8x + 20 = 180 <em>subtract 20 from both sides</em>

8x = 160 <em>divide both sides by 8</em>

3 0

3 years ago

Lindsey bought a new candle and the base of the candle covers an area of 19.625 square inches. She plans on putting the candle i

Natali5045456 [20]

Answer:

-Amy

-The candle will fit.

Step-by-step explanation:

-The candle has a circular base of area $19.625\ in^2$

-The area of a circle is given by the formula:

$A=\pi r^2$

#We substitute the candle's base area in the formula to solve for the bowl's radius;

$A=\pi r^2\\\\19.625=\pi r^2\\\\\\r=\sqrt{\frac{19.625}{\pi}}\\\\=2.499a\approx 2.5\ inches$

The candle has a base radius of approximately 2.5 inches which is equivalent to the bowl's radius.

Hence, Amy is correct and yes, the candle will fit as it is approximately of similar radius.

4 0

3 years ago

Read 2 more answers

Find the local maxima of f ( x ) = 2 x 3 − 30 x 2 + 126 x + 2

PSYCHO15rus [73]

$\text{Consider the function}\\
\\
f(x)=2x^3-30x^2+126x+2\\
\\
\text{To find the local maxima, first we find the critical points.}\\
\text{for critical points set the first derivative 0 and solve for x.}\\
\text{so using power rule of derivatives, we have}\\
\\
f'(x)=2(3x^2)-30(2x)+126(1)+0$

$\Rightarrow f'(x)=6x^2-60x+126\\
\\
\text{now for critical points, we set }f'(x)=0\\
\\
\Rightarrow 6x^2-60x+126=0\\
\\
\Rightarrow 6(x^2-10x+21)=0\\
\\
\Rightarrow x^2-10x+21=0\\
\\
\Rightarrow x^2-7x-3x+21=0\\
\\
\Rightarrow x(x-7)-3(x-7)=0\\
\\
\Rightarrow (x-3)(x-7)=0$

$\Rightarrow x-3=0, \ \ \ \ \ \ \ \ \text{ and } \ \ \ \ \ x-7=0\\
\\
\Rightarrow x=3, \ \ \ \ \ \ \ \ \text{ and } \ \ \ \ \ x=7\\
\\
\text{now to check for maximum minimum, we do second derivative test.}\\
\\
f''(x)=12x-60\\
\\
\text{at x=3, second derivative is}\\
\\
f''(3)=12(3)-60=-24$

$f''(7)=12(7)-60=24>0, \text{ so local minimum occur at x=7.}\\
\\
\text{hence the local maximum value of the function is}\\
\\
f(3)=2(3)^3-30(3)^2+126(3)+2=164$

Hence the local maxima of f is: 164

8 0

4 years ago

50 m + 4 % please help

aleksandr82 [10.1K]

Answer:

52 meters

Step-by-step explanation:

each percent is 1, so 50m plus 4 percent equals 52

6 0

3 years ago

What is the area, in square meters, of the shaded part of the rectangle below?

disa [49]

Answer:

37.5

Step-by-step explanation:

the shaded part forms a trapezoid

we can find the area of the trapezoid itself using the formula

A = (a+b)/2 × h

where a and b = base lengths and h = height

here, we are given that the base lengths are 5m and 10m and the height is 5m

so we have A = (a+b)/2 × h

==> plug in a = 10 , b = 5 and h = 5

A = (10 + 5)/2 × 5

==> add 10 and 5

A = (15)/2 × 5

==> divide 15 by 2

A = 7.5 × 5

==> multiply 7.5 by 5

A = 37.5

4 0

2 years ago