Answer:
Step-by-step explanation:
Suppose you drive a car 392 miles on one tank of gas. The tank holds 14 gallons of gas. This means that
1 gallon of gas would be used to drive 392/14 = 28 miles
a) The number of miles traveled varies directly with the number of gallons of gas used.
Let x =number of gallons of gas you use.
Let y = the number of miles travelled.
Since y varies directly with x, we will introduce a constant of proportionality, k. Therefore,
y = kx
If 28 miles will require 1 gallon of gas, it means
28 = 1×k
k = 28
So y = 28x
b) we want to determine how far you can drive with 3.7 gallons of gas.
x = 3.7
y = 28x = 28×3.7
y = 103.6 miles
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
22 + (30 - 4) divided by 2
30 - 4 = 26
26/2 = 13
22 + 13 = 35
35
18 + (22 - 4) divided by 6
22 - 4 = 18
18 divided by 6 = 3
18 + 3 = 21
21
10, 20w, 2w, and we are factors of 20w and 40wz
Answer:
b i just dat.
Step-by-step explanation:
