Answer:
c=-5
d=1
Step-by-step explanation:
I'm going to reorder the left-hand side. Multiplication is commutative.
Since the bases are the same in 
and the operation is multiplication, I'm going to add the exponents giving me:
So this implies we have two equations to solve:
and 
So the first equation can be solved by dividing both sides by 4 giving you 
.
The second equation can be solved by subtracting 2 on both sides giving you 
.
Draw
Left side:
(1)Square=1 (1)Triangle=5 (1)Circle=6
1+5=6+6=12
Right side: (2)Circle=6
6+6=12
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
5(u+w) it is using distributive property.
The answer is 48--- 64% of 75=48
