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Anastaziya [24]
3 years ago
14

24. Sam, Sonny and Sal are camping in their tents. If the distance between Sam and

Mathematics
2 answers:
AnnZ [28]3 years ago
6 0

Answer:

Step-by-step explanation:

kozerog [31]3 years ago
5 0

Answer:

b. 75°

Step-by-step explanation:

Draw a triangle. Write a person name and a point name (a letter) at each vertex: Sam A, Sonny B, and Sal C at the vertices.

Write the distances as AB = c = 153 ft; AC = b = 201 ft; BC = a = 175 ft.

We are looking for angle B.

Since we have a triangle with three side lengths and no angle measures, we use the Law of Cosines.

b^2 = a^2 + c^2 - 2ac \cos B

201^2 = 175^2 + 153^2 - 2(175)(153) \cos B

40401 = 30635 + 23409 - 53550 \cos B

-53550 \cos B = -13643

\cos B = \dfrac{-13643}{-53550}

\cos B = 0.254771242

B = \cos^{-1} 0.254771242

B = 75^\circ

Answer: b. 75°

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What is the cosine for a angle of 15 degrees?
elena-14-01-66 [18.8K]

Answer:

0.965925826 = 0.97

Step-by-step explanation:

just put in the calculator >>> cos(15)

6 0
3 years ago
Jane sells 8 times as many Volvos as Melissa. If the difference in their sales is 35, how many cars did Jane sell?
Usimov [2.4K]
Here we have 2 variables we need to calculate:
x - how many Volvos Jane sold
y - how many Volvos Melissa sold

We write system of equations:
x = 8*y
x - y = 35
------------
8y - y = 35
7y = 35
y = 5
x = 8*5 = 40

Jane sold 40 cars.
8 0
3 years ago
How do you decompose numbers
Over [174]
Method 1 Decomposing into Hundreds, Tens, and Ones<span>
Understand the difference between "tens" and "ones." ...

Break apart a two digit number. ...

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8 0
3 years ago
9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
3 years ago
PLEASE PLEASE PLEASE HELP TIMEDCan you prove that DE F = HGF Justify your answer. A. Yes, the triangles are congruent by SAS. B.
LenKa [72]

Answer:

A. Yes, the triangles are congruent by SAS.

Step-by-step explanation:

EF = FG and DF = FH-> Given

angle EFD = angle HFG -> Vertical angles are congruent

DE F = HGF -> SAS Triangle Congruence Theorem

6 0
3 years ago
Read 2 more answers
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