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masya89 [10]
2 years ago
15

Write the equation of the line that passes through (-3,6) with a slope of -2

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
6 0

                  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}

       What is the equation of the line that passes through (-3, 6) and has a slope of -2?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond

     

First, we need to write the equation of the line in point-slope form:-

\sf{y-y_1=m(x-x_1)}

Replace y1 with 6, m with -2, and x1 with -3:-

\sf{y-6=-2(x-(-3)}

On simplification,

\sf{y-6=-2(x+3)}

On further simplification,

\sf{y-6=-2x-6}

Add 6 on both sides:-

\it{y=-2x}

<h3>Good luck with your studies.</h3>

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 f(x) = x²<span> - 5x + 1

f(-3) = (-3)</span>² - 5(-3) + 1
<span>
f(-3) = 25


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Answer: f(-3) = 25 (Answer C)
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4 0
4 years ago
A stack of 200 pennies is 1.325 inches tall. Mario guesses that each penny is 0.013 inches thick. Explain how you know Mario’s a
pishuonlain [190]

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200 divided by 1.325 = 0.006625 thats how big each penny is hope this helped! :)

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP
Igoryamba

Answer:

∠1 - 40°

Step-by-step explanation:

∠1 - 40°

b/c it's a right triangle and we have two angles given, 50° and 90°. Add them and subtract by 180° and get 40°.

∠2 - 140°

b/c an exterior (outside) angle is equal to the two most isolated / farthest angles added. The two most is angles are 105° and 35°, add them and get 140°.

∠3 - 40°

b/c ∠'s 1 and 3 are vertical angles meaning they're equal so since ∠1 is 40°, so is ∠3.

∠4 -

b/c ∠' s 2 and 4 are vertical angles meaning they're equal so since ∠2 is 140°, so is ∠4.

∠5 - 35°

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~~

I hope that helps you out!!

5 0
3 years ago
Q10 A student wants to raise £100 for charity.
ElenaW [278]

Answer:

He must charge minimum £0.84 for one hot dog.

Step-by-step explanation:

Ingredients cost for hot dogs at the supermarket,

Price of dog sausages tin of 8 = 50p ≈ £0.5

Price of dog bun packs of 6 = 90p ≈ £0.90

Number of tins required for 150 hot dogs = \frac{150}{8} = 6.25

So student will purchase 7 tins.

Cost of 7 tins = 7 × 0.5

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Number of dog buns packets required = \frac{150}{6} = 25

Cost of 25 packs = 25 × 0.9

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Total cost of the material used for 150 buns = 22.5 + 3.5

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Let the selling price of each hot dog = £x

Then selling price of 150 hot dogs = £150x

Students wants the profit = £100

So, Selling price - Cost price = profit

150x - 26 = 100

150x = 126

x = \frac{126}{150}

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Therefore, he must charge minimum £0.84 for one hot dog.

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