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masya89 [10]
2 years ago
15

Write the equation of the line that passes through (-3,6) with a slope of -2

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
6 0

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\diamond\large\blue\textsf{\textbf{\underline{Given question:-}}}

       What is the equation of the line that passes through (-3, 6) and has a slope of -2?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond

     

First, we need to write the equation of the line in point-slope form:-

\sf{y-y_1=m(x-x_1)}

Replace y1 with 6, m with -2, and x1 with -3:-

\sf{y-6=-2(x-(-3)}

On simplification,

\sf{y-6=-2(x+3)}

On further simplification,

\sf{y-6=-2x-6}

Add 6 on both sides:-

\it{y=-2x}

<h3>Good luck with your studies.</h3>

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Answer:

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Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

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So we are interested on the expected value of A+B, like this

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E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

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The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

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And in order to find the variance for the random variable A+B we can find the individual variances:

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Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

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