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2 years ago

Let the vector v have an initial point at (3,−2) and a terminal point at (3,−7). Determine the components of vector v

Mathematics

2 answers:

zaharov [31]2 years ago

5 0

Your answer should be (0,-5)
hope this helps

kiruha [24]2 years ago

3 0

Answer:

(0,-5)

Step-by-step explanation:

Terminal minus initial. (3-3, -7+2) = (0,-5)

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Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

the temperature at 6:00AM was 0.8F. BY. 3:00pm the temperature had increased to 2.4 F find the differnce between the two tempera

Tom [10]

0.8+2.4= 10.4F it increased 10.4f from 6am to 3am

4 0

3 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\displaystyle\frac{1}{2} x+b$

Determine the y-intercept (b):

$y=\displaystyle\frac{1}{2} x+b$

Plug in the given point (1,3) and solve for b:

$3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}$

Therefore, the y-intercept is $\displaystyle \frac{5}{2}$ . Plug this back into $y=\displaystyle\frac{1}{2} x+b$ :

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

I hope this helps!

8 0

2 years ago

A line is represented by the equation y/x-2=3/11. What are the coordinates of some points that line on the line?

Galina-37 [17]

y/x-2=3/11 would be easier to work with if we were to put it into a more standard form, e. g., y = mx + b.

First, add 2 to both sides, to isolate y/x:

y/x = 3/11 + 22/11 = 25/11.

Next, mult. both sides by x, to get y by itself: y = (25/11)x.

This is your function.

Now make a table. You can choose any x values you want, and then calculate y for each one.

x y

0 0

1 25/11

3 (25/11)*3 = 75/11

Then we have three points on this line: (0,0), (1, 25/11), 3, 75/11). You could obtain more by choosing additional x values.

4 0

3 years ago

Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...

Rama09 [41]

The image is missing, so i have attached it

Answer:

Equation is;

q/sin 105 = 15/sin 30

Step-by-step explanation:

We are given;

Angle Q = 105°

Angle S = 30°

s = 15

From sine rule we know that;

a/sin A = b/sin B = c/sin C.

Thus, applying that to this question, we can find side q.

Thus;. q/Sin Q = s/Sin S

Plugging in the relevant values to obtain ;

q/sin 105 = 15/sin 30

8 0

3 years ago