Answer:
Step-by-step explanation:
x = cost of drink
y = total cost
First information: "one large pizza and 3 medium drinks cost $21.96":
3a + b = 21.96
Second information: "one large pizza and 6 medium drinks cost $30.93":
6a + b = 30.93
{3a + b = 21.96
{6a + b = 30.93
{- 3a - b = - 21.96
{6a + b = 30.93
3a = 8.97
a = 2.99
3a + b = 21.96
3•2.99 + b = 21.96
8.97 + b = 21.96
b = 21.96 - 8.97
b = 12.99
Each drink costs $2.99 and each pizza costs $12.99. The linear function rule is:
y = 2.99x + 12.99
I hope I've helped you.
Answer:
x <= 0 or 1 = < x <= 5.
Step-by-step explanation:
First we find the critical points:
x(x - 1)(x - 5) = 0
gives x = 0, x = 1 and x = 5.
Construct a Table of values:
<u> x < 0 </u> <u>x = 0 </u> 0<u>< x < 1</u> <u>1 =< x <= 5</u> <u>x = 5</u>
x <0 0 >0 <0 0
x - 1 <0 -1 >0 <0 0
x - 5 < 0 0 > 0 <0 0
x(x-1)(x-5) < 0 0 >0 <0 0
So the answers are x =< 0 or 1 =< x <= 5.
Answer:
30 sweets
Step-by-step explanation:
From the above question
The ratio is given as:
Karan : Preeti
2:3
The sum of the proportion = 2 + 3 = 5
Total number of sweets = 50 sweets
The number of sweets Preeti will get is calculated as:
3/5 × 50 sweets
= 30 Sweets
Therefore, the number of sweets Preeti will get is 30 sweets
Answer:
40.1% probability that he will miss at least one of them
Step-by-step explanation:
For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
0.95 probaiblity of hitting a target
This means that 
10 targets
This means that 
What is the probability that he will miss at least one of them?
Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

We want P(X < 10). So

In which

40.1% probability that he will miss at least one of them