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DENIUS [597]
3 years ago
13

Helppp!!!!!!!!!! please

Mathematics
2 answers:
azamat3 years ago
7 0

Answer:

500,000

Step-by-step explanation:

prohojiy [21]3 years ago
7 0
It would be 800,000 100,000 X 2= 200,000 200,000 X 2= 400,000 400,000 X 2= 800,000 its for each 12 minutes and there are 3 times in 36 minutes
You might be interested in
In math class, the girl to boy ratio is 8 to 6. If there are 24 girls in the class, how many boys are there?
Studentka2010 [4]

Answer:

8 : 6 = 24 : 18

Step-by-step explanation:

If there were 24 girls in class, there would be 18 boys.

Girls: 8, 16, 24

Boys: 6, 12 , 18

4 0
3 years ago
Read 2 more answers
del and jen have a joint checking account. their balance at the beginning of October was $6238.67. During the month they made de
dimaraw [331]

Answer:

4778.69 +d-z+b

Step-by-step explanation:

Initial balance of the joint checking account = $6238.67

Deposits in a month gets added in the account = d dollars

Maintenance fee  is deducted in the account = z dollars

Interest on the account is added in the account balance = b dollars

Checks written also gets deducted form the account = $1459.98

Algebraic expression so formed is

6238.67 + d -z+b-1459.98

4778.69 +d-z+b

3 0
3 years ago
70/b+5a-2b<br><br> Evaluate the expression when a=3 and b=10
ozzi
A = 3
b = 10

70/(10) + 5(3) - 2(10)

70/10 = 7

5(3) = 15

2(10) = 20

7 + 15 - 20 =2

2 is your answer

hope this helps
7 0
4 years ago
Read 2 more answers
The spread around a regression modle is measured with the residual standard deviation. True or False
Anna11 [10]

Answer:

True

Step-by-step explanation:

Residual standard deviation is the square root of the residual variance. It is an estimate of the error made on the measurement of the dependent variable.

Thus, the spread around the regression model is usually measured with the residual standard deviation because it is the measurement of standard error between actual and predicted value.

3 0
3 years ago
Find a solution to y'(t) = te^-t satisfying the condition y(1) = 1.
Alex_Xolod [135]

Answer:

y=-e^{-t}(t+1)+1+\frac{2}{e}

Step-by-step explanation:

The given differential equation is

y'(t)=te^{-t}

It can be written as

\frac{dy}{dt}=te^{-t}

dy=te^{-t}dt

Integrate both sides.

\int dy=\int te^{-t}dt

Apply ILATE rule on right side. Here, t is first function and e^{-t} is the second function.

y=t\int e^{-t}-\int (\frac{d}{dt}t\int e^{-t})

y=-te^{-t}-\int (1\times (-e^{-t}))         \int e^{-x}=-e^{-x}+C

y=-te^{-t}+\int e^{-t}

y=-te^{-t}-e^{-t}+C             .... (1)

Initial condition is y(1) = 1. It means at t=1 the value of y is 1.

1=-(1)e^{-t}-e^{-(1)}+C

1=-e^{-1}-e^{-1}+C

1=-2e^{-1}+C

1=-\frac{2}{e}+C

Add \frac{2}{e} on both sides.

1+\frac{2}{e}=C

Substitute the value of C in equation (1).

y=-te^{-t}-e^{-t}+1+\frac{2}{e}

y=-e^{-t}(t+1)+1+\frac{2}{e}

Therefore, the solution of given initial value problem is y=-e^{-t}(t+1)+1+\frac{2}{e}.

4 0
3 years ago
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