If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Product is multiplication.
Since the answer needs to be greater than 2 either the fraction needs to be an improper fraction ( meaning the fraction would be greater than 1) or the whole number would need to be greater than 2.
One answer would be 5 x 2/3 = 3 1/3
The answer is c. 64 divided by 4 is 16 and 8 divided by 5 is 16
Answer:
B) 4
Step-by-step explanation:
There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has an area of 20 square inches. If the actual outbuilding has a wall length of 10 feet, what is the length of that wall on the blueprint . A) 3 B) 4 C) 5 D) 6
The length of the wall on the blue print can be calculated as:
20 square feet ÷ 5
= 4 feet
Answer:
D) v = -2,000y + 20,000.
Step-by-step explanation:
The question gives a linear relationship between two quantities. This means that the relationship between the initial value of the car and the amount it depreciates each year is proportional, or constant. Since the value of the car decreases by 10% of its initial value each year, then each year the value will decrease by 10% of 20,000 or 0.10 x 20000 = $2,000. Since we know the value is decreasing each year, this amount would be subtracted from the initial value of $20,000. So, D) v = -2,000y + 20,000 would be the only equation that represents this scenario.
