If the equation is ![y = \sqrt[3]{x-1}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx-1%7D)
then the domain is the set of all real numbers.
We can replace x with any real number and compute to get some real number output for y. There are no division by zero restrictions to worry about, or issues with taking a square root of a negative number (since this isn't really a square root function).
The cube root of a negative number is negative. For example, ![\sqrt[3]{-64} = -4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-64%7D%20%3D%20-4)
because (-4)^3 = (-4)*(-4)*(-4) = -64.
In interval notation, the domain would be written as 
to indicate the entire real number line.
Step-by-step explanation:
arranging in ascending order is simply arranging from the smallest to the largest.
12.4654,156.6100,267.0918,295.6097,784.7068
I hope this helps
Answer:
Serina should have solved for x in the second equation because it has a coefficient of 1.
Step-by-step explanation:
we have
----> equation A
---> equation B
we know that
To solve the system of equations in the most efficient way, solve for x equation B and then substitute the value of x in equation A
so
----> equation C
substitute equation C in equation A
solve for y
Find the value of x
substitute the value of y in the equation C
The solution is (3,4)
therefore
Serina should have solved for x in the second equation because it has a coefficient of 1.
Answer:
w<4
Step-by-step explanation:
divide both sides by 8. no need to flip the sign because 8 is positive
8/8w<32/8
w<4
