What is the surface area of a cube that has a radius of 9 ft and height of 3 ft
1 answer:
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Answer:
<em>797.0ft²</em>
Step-by-step explanation:
<u>Find a related diagram attached</u>
Area of the gate = Area of the semicircle + Area of the Rectangle
Area of the semicircle = πr²/2
r is the radius
From the diagram, radius r = 20/2 = 10ft
Area of the semicircle = 3.14(10)²/2
Area of the semicircle = 3.14(100)/2
Area of the semicircle = 314/2
Area of the semicircle = 157ft²
Area of the rectangle = Length * Width
Area of the rectangle = 20*32
Area of the rectangle = 640ft²
Area of the gate = 157 + 640
Area of the gate = 797ft²
<em>Hence the area of the gate is 797.0ft²</em>
