14+m=56
m=56-14(minus 56 from both side)
M=42
The slope-intercept form of a line:
m - slope
b - y-intercept
Convert 2x + 3y = -6 to the slope-intercet form:
<em>subtract 2x from both sides</em>
<em>divide both sides by 3</em>
Let 
and 
We have 
Therefore
We have the equation of a line:
Put the coordinates of the point (0, 0) to the equation:
Answer: 
Answer:
Step-by-step explanation:
1) 2x -y = 1 -------1
3x - y = -6 ------2
Subtract eqn 2 from eqn 1
-x = 1--6 = 7
x = -7
Put x= -7 in eqn 1
2*-7-y = 1
-14-y = 1
- y = 15
y = -15
2) 4x +2y = 10------1
y = 4x + 2--------2
Put eqn 2 in eqn 1
4x + 2 ( 4x+ 2) = 10
4x + 8x + 4 = 10
12x = 6
x = 6/12 = 1/2
Put x = 1/2 in eqn 2
y = 4* 1/2 + 2= 2 + 2
= 4
3) 6x - y = 2------1
y = 3x + 4---------2
Put eqn 2 in eqn 1
6x - (3x +4) = 2
6x - 3x - 4 = 2
3x = 6
x = 2
y = 3*2 + 4 = 6 + 4
= 10
All are relations except for relation 3
I think it is c, I could be wrong though
