Answer:
(x + 3, y - 2)
Step-by-step explanation:
we know that
The rule of the transformation T is equal to
T: pre-image → image
T: (x, y) → (x',y')
T: (x, y) → (x - 3, y + 2)
so
x'=x-3 ----> x=x'+3
y'=y+2 ----> y=y'-2
The rule of the inverse of transformation T -1 is equal to
T-1: image → pre-image
T-1: (x', y') → (x,y)
T-1: (x', y') → (x'+3, y'-2)
Answer:
ABC ~ EDF
Step-by-step explanation:
By the order of the letters, we can determine which triangles are similar.
We know that Angle D is congruent to Angle B. So we have to look for a set of triangles where D and B have the same place holders.
For example, if D is the first letter, then B also has to be the first letter.
The same thing applies for Angle E, and Angle A, since they are congruent to each other.
Wherever Angle E is, Angle A has to be in that same place holder.
Triangle ABC, has Angle B, as the second angle. Therefore we know the similar triangle has to be _D_.
Similarly, Angle A is congruent to Angle E, so we know that Angle E has to be in the first place holder. ED_
By process of elimination we know that the only corresponding angles left are C and F, they must be congruent. So the last thing to write is F.
Triangle ABC ~ Triangle EDF
Answer:
C =(x-3)(x-2)/x
or
x²-5x+6/x
Step-by-step explanation:
2x^2 - 4x - 6/x + 2 * x^2 - 4/2x^2 + 2x
Factorizing the given factors
1) 2x^2 - 4x - 6
= 2x^2 - 6x+2x - 6
= 2x(x-3) +2(x-3)
= (x-3)(2x+2)
2) x^2 - 4
= (x+2) (x-2)
3) 2x^2 + 2x
= 2x( x+1)
Putting the factors
(x-3)(2x+2)/x + 2 * (x+2) (x-2)/2x( x+1)
= (x-3)(2x+2) (x-2)/2x( x+1)
= 2(x-3)(x+1) (x-2)/2x( x+1)
=(x-3)(x-2)/x
Now multiply
(x-3)(x-2) =x²-5x+6
Then the answer becomes x²-5x+6/x
Answer:
Diameter: 4
Radius: 2
Equation: ( x-3 ) + ( y + 2) = 4
Answer:
<em>To find a positive and a negative angle coterminal with a given angle, you can add and subtract if the angle is measured in degrees or if the angle is measured in radians .</em>