The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:

To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
I think it’s the last one
Answer:
−27u + 8v
Explanation:
−3(4u − v) − 5( − v + 3u)
[ Distribute ]
= (−3)(4u) + (−3)(−v) + (−5)(−v) + (−5)(3u)
= −12u + 3v + 5v + −15u
[ Combine Like Terms ]
= −12u + 3v + 5v + −15u
= (−12u + −15u) + (3v + 5v)
= −27u + 8v
- PNW
Question 4- is 32.25
question 5- is 12.4
question 6 -is 14/17
question 7 - is 10.7
Answer:
See explanation
Step-by-step explanation:

By the distributive property this is equal to:

Hope this helps!