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prohojiy [21]
3 years ago
6

Is the second side “WY and ZY” or the other way around?

Mathematics
1 answer:
sveta [45]3 years ago
5 0

Answer:

yes it's wy =zy you may write it

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Which expressions are factors of the expression<br><br> -24xyz - 12xy + 20xyz
Alex17521 [72]

Answer:

xy

2xy

4

Step-by-step explanation:

A factor is a number of term you can factor out of each part of the expression/ or divide it by.

In -24xyz - 12xy + 20xyz

All three parts have xy, so it is a factor

All three don't have 12xz, because -12xy doesn't have z variable for instance.

All three have 2xy.

All three can't factor out 3y, because you can't divide 20 by 3 nicely.

All three can't factor out 4yz, because middle term -12xy doesn't have z.

All three can't factor out 12, because you can't nicely divide 20/12.

All three can factor out 4, because -24, -12, and 20 are all divisible by 4.

please give thanks by clicking heart button :)

6 0
3 years ago
Synplifying expressions<br> 4x-2x-20x+x
Sladkaya [172]

Answer:

-17x is the answer mark me brainliest

7 0
3 years ago
Read 2 more answers
I need help ! ASAP !
svetoff [14.1K]

Answer:

288

Step-by-step explanation:

There are 8 fluid ounces in a cup so that would equate to

8 x 36 = 288

288 fluid ounces a minute

7 0
3 years ago
Which is the vertex of x2 + 10x = -17 <br><br> (-5,-8)<br><br> (5,8)<br><br> (-5,8)<br><br> (5,-8)
ad-work [718]

Answer:

vertex = (- 5, - 8)

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c = 0 : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

Given x² + 10x = - 17 ( add 17 to both sides )

x² + 10x + 17 = 0 ← in standard form

with a = 1, b = 10, c = 17, then

x_{vertex} = - \frac{10}{2} = - 5

Substitute x = - 5 into the quadratic for the corresponding value of y

y = (- 5)² + 10(- 5) + 17 = 25 - 50 + 17 = - 8

Hence vertex = (- 5, - 8)

4 0
4 years ago
Please help! Brainliest
Mama L [17]

1.301

Explanation:

Given:

\log_a5 \approx 0.699 and \log_a2 \approx 0.301

Note that from the properties of logarithms,

\log_a20 = \log_a(5×4)

\:\:\:\:\:\:\:\:\:\:= \log_a(5×2^2)

\:\:\:\:\:\:\:\:\:\:=\log_a5 + \log_a(2)^2

\:\:\:\:\:\:\:\:\:\:=\log_a5 + 2\log_a2

\:\:\:\:\:\:\:\:\:\:\approx 0.699 + 2(0.301)

\:\:\:\:\:\:\:\:\:\:= 1.301

6 0
3 years ago
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