Answer:
![\boxed{\boxed{\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}=d}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Csqrt%5B3%5D%7Bd%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bd%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bd%7D%3Dd%7D%7D)
Step-by-step explanation:
The given expression is,
![=\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7Bd%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bd%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bd%7D)
It can also be written as,
The exponent product rule of algebra states that, while multiplying two powers that have the same base, the exponents can be added.
As here all the terms have same base i.e d, so applying the rule
Assuming that Ralph budgeted $180 instead of $175 entertainment. He spent $35 per date and let "x" be the number of dates he attended. He spent $15 to go out with friends and let "y" the number of times that he go out with friends.
The correct expression is the "B" which is 35x + 15y =180.
Remember that
try and simpliy each first
4y/14=(2/2)(2y/7)=2y/7
so 2x/7 divided by 2y/7
=
Answer:
improper question
Step-by-step explanation:
-_-
