Solve each equation with (0, 3)
y = -x + 3
3 = -0 + 3
y = 3 (correct since y = 3 in (0, 3))
y = 2x - 3
3 = 2(0) - 3
3 = 0 - 3
3 = -3 (incorrect since it isn't equal)
So... No, because it does not check in the second equation.
Best of Luck!
Answer:
Step-by-step explanation:
Let's solve for f.
y=3x−2x2findf(3)
Step 1: Flip the equation.
−6df2inx2+3x=y
Step 2: Add -3x to both sides.
−6df2inx2+3x+−3x=y+−3x
−6df2inx2=−3x+y
Step 3: Divide both sides by -6dinx^2.
−6df2inx2
−6dinx2
=
−3x+y
−6dinx2
f2=
3x−y
6dinx2
Step 4: Take square root.
f=√
3x−y
6dinx2
or f=−√
3x−y
6dinx2
Answer:
f=√
3x−y
6dinx2
or f=−√
3x−y
6dinx2
120 cupcakes
Even # rows
Odd # columns
12: 1, 2,3,4,6, 12 (integers?)
I see only one arrangement with odd column & even rows
3 columns, 40 rows
That's mainly because 120 is an even number.
Answer:
19 lbs and 8 oz
Step-by-step explanation:
12 + 6 = 18 13 + 11 = 24 24 oz = 1 lb and 8 oz 1 lb and 8 oz + 18 = 19 lbs and 8 oz
The zeros of the polynomial are <span>1, 2, -2 and -3, so this polynomial must have at least one of each of these factors:
(x-1), (x-2), (x-(-2)), and (x-(-3)); rewriting: </span>(x-1), (x-2), (x+2), and (x+3).
Thus, any such polynomial must have a factor (x-1)(x-2)(x+2)(x+3).
The simplest such polynomial we can think of, is p(x)=(x-1)(x-2)(x+2)(x+3).
To write in standard form, lets first multiply the factors two by two as follows:
by the difference of squares formula,
.
Next, we multiply our results:
.
Answer: