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Anettt [7]
3 years ago
7

HELP ASAP PLEASE HELP QUICK!!!!

Mathematics
2 answers:
kati45 [8]3 years ago
7 0

Answer:

4:5

Step-by-step explanation:

masha68 [24]3 years ago
6 0

Answer:

4:5 that's last answer i got

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Graph Y+5=-2x and explain how you did it.
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6 0
2 years ago
HELP! I will give BRAINLIEST!! Please EXPLAIN Olga tried to solve an equation step by step. ​ Equation: 1/4 ( 1/3k + 9) = 6 ​ St
Vera_Pavlovna [14]

Answer:

Olga's mistake was in Step 3 because she divided the entire equation by 3 instead of dividing it by 1/3.

3 0
3 years ago
What is the value of a in the equation a = 2 + 3a + 6?
gulaghasi [49]
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3 0
3 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
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