An2=1
Step-by-step explanation:
i got ur point hehe. gotta go my own way
You first separate the triangle from the rectangle. Then multiply one side be one side.
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Since it is an equality that means the left side of the equation (x/8) has to be equal to the right side of the equation (28/32). One way you can solve for x is to isolate it. Since it’s an equality like we said you have to do to the left side the same that you would do to the right side to isolate x. So if I multiply by 8 on the left I need to also multiply by 8 on the right. So 8* (x/8) becomes just x since 8x/8 becomes 8/8 * x which is 1 *x. On the right side we do 8 *(28/32) which becomes 28 * 8/32 which becomes 7. So x = 7.
You first must find the 18% of the fish population.
You multiply 500 by .18 . You are supposed to get 90.
90 is the 18% fish increase.
Then you just add 500 + 90 and you will get 590 fish that are now in the school.
