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3 years ago

Select all points that are on the graph of the line

Mathematics

1 answer:

Marysya12 [62]3 years ago

7 0

Answer:

0,3

Step-by-step explanation:

Well 0,3 is the only one that is on here... I apologize if I am wrong!

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sergiy2304 [10]

Answer:

Q, R

Step-by-step explanation:

All of the listed sets of numbers are Real numbers. The fraction is not an integer, so is not in sets I or N. Because it is a fraction, it is in set Q, and because R includes Q, ...

the number is in sets Q and R

8 0

2 years ago

Simplify this expression 6g^3h^3 /15g

mina [271]

Answer:

Step-by-step explanation:

$\frac{6g^{3}*h^{3}}{15g}=\frac{2g^{2}*h^{3}}{5}$

3 0

3 years ago

Read 2 more answers

209 is what percent of 475?

professor190 [17]

Answer:

44%

Step-by-step explanation:

1) You divide 209 by 475

2) Take 0.44 and move the decimal over 1 place to make <u>44%</u>

8 0

3 years ago

The selling price of the Robertsons family house dropped from $500,000 to $250,000. What was the percent decrease in the value o

Alexus [3.1K]

Answer:

50%

Step-by-step explanation:

You can literally do it mentally lol

$500,000

- <u>$250,000</u>

$250,000

so by common sense, it's 50%

Hope it helped!

5 0

2 years ago

Read 2 more answers

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago