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Brrunno [24]
2 years ago
9

Find the value of this:

Mathematics
1 answer:
mixer [17]2 years ago
4 0
1 3 /10. That’s the answer because you have to carry over the six bc 2/10 is less then 9/10
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A flyer is spread by people
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A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of - Brainly.in Find an answer to your question A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of flyers to six people. there you go buuuuuudy

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Blueberries are on sale for $2.80 per pint. The regular price is $3.50 per pint. What is the percent of decrease?
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2 years ago
What is 5.3809 rounded to the nearest thousandth?<br>Enter your answer ​
Hatshy [7]

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5 0
3 years ago
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Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

P(X>140)=P(Z>\frac{140-112}{14})

P(X>140)=P(Z>\frac{28}{14})

P(X>140)=P(Z>2)

P(X>140)=1-P(Z

The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

P(X>140)=0.0228

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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