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steposvetlana [31]
2 years ago
15

Can someone explain how to get the answer, please? Thanks!

Mathematics
1 answer:
Irina18 [472]2 years ago
4 0
The mean is 10,

The median is 10,

And there is no mode.



The mean of a set of numbers is the sum divided by the number of terms,

7+15+12+6+10=50

There are 5 numbers in the set,

50/5=10.
10 is the mean.



Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers,

6, 7, 10, 12, 15,

10 is in the middle so it is the median.



The mode is the element that occurs most in the data set. In this case, all elements occur only once, so there is no mode.




Just so you don’t confuse the data with the group sets,

The actual data set is 7, 15, 12, 6, and 10

This data paired with score column or group set means that,

10 people got a score of 1-10
6 people got a score of 11-20
12 people got a score of 21-30
15 people got a score of 31-40
And 7 people got a score of 41-50 :)
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I need help with the answer.
Alchen [17]

Answer:

a) a = 12s

Step-by-step explaination:

5 0
3 years ago
the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers
notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

y = k * x

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

476 = k * 17

From here, we clear the value of k:

k = \frac{476}{17}\\k = 28

Therefore, the relationship is:

y = 28x

For 1428 kilometers we have:

1428 = 28x

Clearing the amount of fuel we have:

x = \frac{1428}{28}\\x = 51

Answer:

51 liters of fuel are required for the vehicle to travel 1,428 kilometers

3 0
3 years ago
For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
3 years ago
Solve for x. ax-bx=k​
dolphi86 [110]

Answer:

x= k/a-b

Step-by-step explanation:

Move all terms to the left side and set equal to zero as well as each factor.

Hope this helps.

3 0
3 years ago
Read 2 more answers
What is 2,792 times 39?
Mumz [18]
108,888 is your answer hoped i helped :3
7 0
3 years ago
Read 2 more answers
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