What is the perimeter of ABC?Perimeter = ___ units.

Mathematics

1 answer:

MAVERICK [17]3 years ago

6 0

Answer:

12 units

Step-by-step explanation:

From the given figure,

AB=4 units & BC=3 units

By Pythagoras Theorem, $AC^{2} = AB^{2} + BC^{2}$

Here, $AC^{2} = 4^{2} + 3^{2}$

Thus, AC=5 units

Now, perimeter of triangle is equal to the sum of all sides.

Perimeter = AB + BC + AC = 4 + 3 + 5 = 12 units

You might be interested in

What is the slope of a line perpendicular to the line whose equation is 2x+3y=21. Fully simplify your answer.

erastova [34]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

therefore then

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}$