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garri49 [273]
3 years ago
14

PLS HELP 50 POINTS

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

\text{Volume of prism made by }\Delta XYZ=2304\text{ in}^3  

Step-by-step explanation:

Let us assume that both prisms are similar, so we can use proportions to solve for the volume of prism made by triangle XYZ.

Let us find the proportion between the sides of both triangles.

\frac{\text{Side of triangle XYZ}}{\text{Side of triangle PQR}}=\frac{24}{36}

\frac{\text{Side of triangle XYZ}}{\text{Side of triangle PQR}}=\frac{12*2}{12*3}

\frac{\text{Side of triangle XYZ}}{\text{Side of triangle PQR}}=\frac{2}{3}

Since for volume of triangular prism we multiply base area and height of the prism, this means we will have to multiply the proportion of each side length 3 times to find the proportion of volumes between our both prism.

So we can set proportion for volume of both prisms as:

\frac{\text{Volume of prism made by triangle XYZ}}{\text{Volume of prism made by triangle PQR}}=(\frac{2}{3})^3  

\frac{\text{Volume of prism made by triangle XYZ}}{\text{Volume of prism made by triangle PQR}}=\frac{8}{27}

Upon substituting volume of prism made by triangle PQR we will get,

\frac{\text{Volume of prism made by triangle XYZ}}{7776\text{in}^3}=\frac{8}{27}    

Let us multiply both sides of our equation by 7776 cubic inches.

\frac{\text{Volume of prism made by triangle XYZ}}{7776\text{ in}^3}*7776\text{ in}^3=\frac{8}{27}*7776\text{ in}^3

\text{Volume of prism made by triangle XYZ}=8*288\text{ in}^3

\text{Volume of prism made by triangle XYZ}=2304\text{ in}^3  

Therefore, the volume of prism made by triangle XYZ is 2304 cubic inches.

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15 POINTS :)<br><br> Solve the inequality. <br> -3x+4&lt;25
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Answer:

x > -7

Step-by-step explanation:

-3x + 4 < 25

-3x + 4 - 4 < 25 - 4

-3x < 21

-3x/-3 < 21/-3

x > -7

May i have brainliest? :)

6 0
3 years ago
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How do you solve for the value of a radius
34kurt
To calculate the radius of a circle by using the circumference, take the circumference of the circle and divide it by 2 times π. For a circle with a circumference of 15, you would divide 15 by 2 times 3.14 and round the decimal point to your answer of approximately 2.39. Be sure to include the units in your answer. Or just 1/2 the diameter :p
Hope this helps!
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4 years ago
Is this decreasing or increasing? (1,4) (6,-1)
Nostrana [21]

Answer:

Decreasing

Step-by-step explanation:

It's a linear line going down from left to right

3 0
4 years ago
Find the range of the function for the fiven domain. f(x)= 3x-8; {-2, -1, 0, 1, 2}
ryzh [129]
<span>f(x)= 3x-8

x = -2,  </span><span>f(x)= 3(-2) -8 = -6 - 8 = -14
</span>x = -1,  f(x)= 3(-1) -8 = -3 - 8 = -11
x = 0,  f(x)= 3(0) -8 = 0 - 8 = -8
x = 1,  f(x)= 3(1) -8 = 3 - 8 = -5
x = 2,  f(x)= 3(2) -8 = 6 - 8 = -2
Domain <span> {-2, -1, 0, 1, 2}
</span>Range: <span> {-14, -11, -8, -5, -2}
</span>
answer
Range:  {-14, -11, -8, -5, -2}
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4 years ago
Find angle ADB of the equation
Aloiza [94]

Answer:

m\angle ADB = 59\°.

Step-by-step explanation:

Given:

\angle BDC = 31\°

We need to find \angle ADB.

Solution:

Now we can see that given figure is a rectangle with diagonals drawn in it.

So by properties of rectangle which states that;

"All angles of a rectangle are 90°."

So we can say that;

\angle A = \angle B = \angle C = \angle D = 90\°

But

\angle D = \angle BDC + \angle ADB

Substituting the values we get;

31\°+\angle ADB = 90\°

Subtracting both side by  by 31 we get;

31\°+\angle ADB -31\°= 90\°-31\°\\\\m\angle ADB = 59\°

Hence m\angle ADB = 59\°.

8 0
4 years ago
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