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3 years ago

An object is launched at 29.4 meters per

Mathematics

1 answer:

Lerok [7]3 years ago

4 0

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

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By factoring, identify the zeros of the quadratic function f (x) = x²-9x-22

vovikov84 [41]

Answer:

x= -2, x= +11

Step-by-step explanation:

I hope this is right!

To factorise, we need two numbers that add to make -9 and multiply together to make -22.

2 - 11 works, so we put it in the brackets in this order.

(x + 2) (x - 11)

so x + 2 = 0 and x - 11 =0

but we could also simplify this to say that x could be either -2 or + 11.

I hope this helps.

Have a lovely day.

7 0

2 years ago

Jonathan runs 4 days a week. Each day, he runs 4 laps that are each 2 miles long. He spends 208 minutes running each week. He ru

fredd [130]

4 laps x 2 miles = 8 miles total

8 miles x 4 days = 32 total miles per week

208 / 32 = 6.5 minutes per mile

4 0

4 years ago

Plz solve this question

Mkey [24]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Simplify ⇨ 1/x(x+a) + 1/x(x-a)

$\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}$

$\sf\frac { 1 } { x ( x + a ) } + \frac { 1 } { x ( x - a ) } \\$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of $x\left(x+a\right)$ and $x\left(x-a\right)$ is $x\left(x+a\right)\left(x-a\right)$ . Multiply $\frac{1}{x\left(x+a\right)} times \frac{x-a}{x-a}$ . Multiply $\frac{1}{x\left(x-a\right)} times \frac{x+a}{x+a}$ .

$\sf\frac{x-a}{x\left(x+a\right)\left(x-a\right)}+\frac{x+a}{x\left(x+a\right)\left(x-a\right)} \\$

Because $\frac{x-a}{x\left(x+a\right)\left(x-a\right)}$ and $\frac{x+a}{x\left(x+a\right)\left(x-a\right)}$ have the same denominator, add them by adding their numerators.