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Irina-Kira [14]
2 years ago
10

how do the boiling point and freezing point of a solution of water and calcium chloride at standard pressure compare to the boil

ing point point and freezing point of water at standard pressure
Chemistry
1 answer:
Snezhnost [94]2 years ago
3 0
Both the increase in the boling point and the depression on the freezing point are colliative properties.

This is, they are proportional to the number of particles dissolved in the solvent, which is measured by the molality of the solution and the factor i (Van'f Hoff).

The answer to the question is that 1) the boling point of a solution of water and calcium chloride at standard pressure will be higher than the normal boiling point of pure water, and 2) the freezing point of a solution of water and calcium chloride at standard pressure will be lower than the normal freezing point of pure water.
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A reaction produces 10.5 L if oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield ? (One mole of any
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To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,

 PV = nRT

If we are to retain constant the variable n and V. 

The percent yield can therefore be solved through the following calculation,

   n = (10.5 L)/(22.4 L)   x 100%

Simplifying,
    n = 46.875%

Answer: 48.87%
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2 years ago
You determine the volume of your plastic bag (simulated human stomach) is 1.08 L. How many grams of NaHCO3 (s) are required to f
dsp73

Answer:

3.636 grams of sodium bicarbonate is required.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 753.5 mmHg = 0.9914 atm

(1 atm = 760 mmHg)

V = Volume of gas = 1.08 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 24.5 °C= 297.65  K

Putting values in above equation, we get:

(0.9914 atm)\times 1.08 L=n\times (0.0821L.atm/mol.K)\times 297.65K\\\\n=0.0438 mole

Percentage recovery of carbon dioxide gas =  49.4%

Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole

\frac{49.4}{100}\times  0.0438 mol=0.02164 mol

2NaHCO_3\righarrow Na_2CO_3+H_2O+CO_2

According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.

Then 0.02164 moles f carbon dioxide will be obtained from:

\frac{2}{1}\times 0.02164 mol=0.04328 mol

Mass of 0.04328 moles pf sodium bicarbonate:

0.04328 mol × 84 g/mol = 3.636 g

3.636 grams of sodium bicarbonate is required.

5 0
3 years ago
Bromine gas in a container is heated over a flame. What happens to the average kinetic energy of the bromine particles? It decre
Hatshy [7]

Answer: B. It increases quickly

Explanation:

7 0
3 years ago
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An oily liquid with a cheesy, waxy odor like that of goats or other barnyard animals is caproic acid, a compound containing carb
Zinaida [17]

The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

  • Mass of H₂O = 20.99 g
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 4

Mass of H = 0.44 g

How to determine the mass of O

  • Mass of compound = 4.30 g
  • Mass of C = 2.67 g
  • Mass of H = 0.44 g
  • Mass of O =?

Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

Mass of O = 1.19 g

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

Learn more about empirical formula:

brainly.com/question/9459553

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Name the two subatomic particles found in the nucleus.
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i can think of 3 subatomic particles found in a nucleus protons, neutrons, and electrons

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