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mamaluj [8]
2 years ago
11

Three apprentice tailors (X, Y, and Z) are assigned the task of measuring the seam of a pair of trousers. Each one makes three m

easurements. The results in inches are X (26.5, 26.6, 26.4); Y (27.8, 27.3, 27.7); Z (26.9, 27.2, 27.1). The true length is 27.0 in. Comment on the precision and the accuracy of each tailor's measurements.
Chemistry
1 answer:
Taya2010 [7]2 years ago
4 0

Answer:

Explanation:

<u>Precision generally refers to the repeatability of measurements. That is, the closeness of repeated meaurements in values. Accuracy, on the other hand, refers to the closeness of a measured value to the true value.</u>

For apprentice X, the three measurements taken (26.5, 26.6, 26.4) were close in values with an average of 26.5 and a mean deviation of 0.07. Hence, the apprentice is said to be precise in measurement. However, the average of the measurement is quite far from the true length of meaurement. Hence, the apprentice is inaccurate.

Apprentice Y had a mean measurement value of 27.6 and a mean deviation of 0.2. The measurements are far from each other and the apprentice is therefore said to be far from being precise. The mean measurement value is also far from true value. Hence the apprentice is also inaccurate in his/her measurement.

Apprentice Z has a mean measurement of 27.07 and a mean deviation of 0.11.  The repeated measurements were close enough to be precise while the average is also close to the true length, and hence, the measurement is said to be accurate.

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an atmosphere is considered hazardous if it contains a hazardous gas in excess of 10 percent of the hazardous material's:
svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

What is hazardous atmosphere?

It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes

  • Flammable gas, vapor, or mist in excess of 10 percent of lower flammable limit (LFL)
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What is lower flammable limit?

  • It means the lowest concentration of a material that will propagate a flame.
  • The LFL is usually expressed as percent by volume of material in air (or other oxidant)
  • Atmospheres with concentration of flammable vapors at or above 10 percent of lower explosive limit (LEL) are considered hazardous when located in confined spaces.
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6 0
1 year ago
Find the force of gravity of 1000 kg car.
ANEK [815]

Answer:

The force of gravity acting on the car is <u>9800 N vertically downward.</u>

Explanation:

Given:

Mass of the car given is 1000 kg.

We know that the force of gravity is the force applied by the center of Earth on any body. The force of gravity is also called the weight of the body and always act towards the center of the Earth.

From Newton's second law, we know that the force acting on a body is equal to its mass and acceleration.

Here, the acceleration acting on the car is due to gravity and thus has a constant value of 9.8 m/s² on the surface of Earth.

Therefore, the force of gravity acting on the car is given using the Newton's second law as:

Force of gravity = Mass of car \times Acceleration due to gravity.

Force of gravity = (1000 kg) \times (9.8 m/s²)

Force of gravity = 9800 N          [1 kg.m/s² = 1 N]

Therefore, the force of gravity acting on the car is 9800 N vertically downward.

6 0
3 years ago
To calculate the freezing point depression ___ solution's freezing point and the freezing point of it's pure solvent.
murzikaleks [220]
I'm sure that to calculate the freezing point depression <span>subtract</span> solution's freezing point and the freezing point of it's pure solvent. According to the formula.
8 0
2 years ago
6) A student measures out 96.21 g of sulfur for an experiment. How many moles of Sulfur are in this
barxatty [35]

Atomic mass of Sulfur = 32g

32g of Sulfur is one mole.

1g of Sulfur is \frac{1}{32} moles

96.21g of Sulfur is \frac{96.21}{32} moles=> 3moles(appx)

5 0
3 years ago
Read 2 more answers
What concentration of monosodium phosphate would be required to make a solution of pH 7.4 with 0.2 M disodium phosphate ( pKa
denis-greek [22]

Answer:

The concentration of monosodium phosphate is 0.1262M

Explanation:

The buffer of H₂PO₄⁻ / HPO₄²⁻ (Monobasic phosphate and dibasic phosphate has a pKa of 7.2

To determine the pH you must use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is molarity of the conjugate base of the weak acid, [HA].</em>

For H₂PO₄⁻ / HPO₄⁻ buffer:

pH = 7.2 + log [HPO₄⁻² ] / [H₂PO₄⁻]

As molarity of the dibasic phosphate is 0.2M and you want a pH of 7.4:

7.4 = 7.2 + log [0.2] / [H₂PO₄⁻]

0.2 = log [0.2] / [H₂PO₄⁻]

1.58489 = [0.2] / [H₂PO₄⁻]

[H₂PO₄⁻] = 0.1262M

<h3>The concentration of monosodium phosphate is 0.1262M</h3>

<em />

8 0
3 years ago
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