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jok3333 [9.3K]
2 years ago
7

The diameter of a circle is 6 units. What is the radius of the circle?

Mathematics
1 answer:
KengaRu [80]2 years ago
3 0

Answer:

3

Step-by-step explanation:

The radius is half of the diameter so 6/2 is 3

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An international company has 23,200 employees in one country. If this represents 26.7% of the company's employees, how many empl
omeli [17]

Answer:

Total number of employees = 86,891 employees

Step-by-step explanation:

Let

x = total number of employees

26.7% of x = 23,200

26.7/100 * x = 23,200

0.267 * x = 23,200

0.267x = 23,200

x = 23,200/0.267

x = 86,891.385767790

approximately 86,891 employees

Total number of employees = 86,891 employees

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3 years ago
A. Rotation of 180º and then a reflection across the x-axis.
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C.

Hope this helps!

Please vote brainliest

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3 years ago
The number doing the dividing in a division problem
Pavlova-9 [17]

Answer:

divisor

Step-by-step explanation:

I just looked it up bro lol

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3 years ago
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3. Marco's Pizzeria has a pizza deal of 5 slices for $6. New York Slice has a pizza deal of 4 slices for $5. Which pizza place h
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3 years ago
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A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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