Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A
A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11
B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29
Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18
<em><u>The solution is (4, 4)</u></em>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

Make the right side of equation 0

<em><u>Solve by quadratic equation</u></em>

<em><u>Substitute x = 4 in eqn 2</u></em>
y = 2(4) - 4
y = 8 - 4
y = 4
Thus solution is (4, 4)
Answer:
100
Step-by-step explanation:

1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²

2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.