Answer:
x= -40
Step-by-step explanation:
Cost
C(x)=1,600+20x
P(x)=100-x
Revenue=x*p(x)
=x*(100-x)
=100x-x^2
Cost=Revenue
1600+20x=100x-x^2
1600+20x-100x+x^2=0
1600-80x+x^2=0
Solve using quadratic formula
Formula where
a = 1, b = 80, and c = 1600
x=−b±√b2−4ac/2a
x=−80±√80^2−4(1)(1600) / 2(1)
x=−80±√6400−6400 / 2
x=−80±√0 / 2
The discriminant b^2−4ac=0
so, there is one real root.
x= −80/2
x= -40
Answer:
The maximum volume of the open box is 24.26 cm³
Step-by-step explanation:
The volume of the box is given as
, where
and
.
Expand the function to obtain:

Differentiate wrt x to obtain:

To find the point where the maximum value occurs, we solve



Discard x=3.54 because it is not within the given domain.
Apply the second derivative test to confirm the maximum critical point.
, 
This means the maximum volume occurs at
.
Substitute
into
to get the maximum volume.

The maximum volume of the open box is 24.26 cm³
See attachment for graph.
Hey there <span>angelinarigole!
Question:
</span><span>To find the unit rate for $182
----------
14feet
Answer:
</span><span>Divide both 182 and 14 by 14.
182</span>÷14=$13
14÷14=1
Hope this helps!
-Jayden
Answer:
f(x + 1) = x² - x
Step-by-step explanation:
f(x) = x² - 3x + 2 when f(x + 1)
f(x + 1) = (x + 1)² - 3(x + 1) + 2
f(x + 1) = (x² + 2x + 1) + (-3x - 3) + 2
f(x + 1) = x² - x + 0
f(x + 1) = x² - x
Best of Luck!
The answer is

To figure this out, convert both numbers to fractions. 1.03 = 1

and (-10.3) = -10

. Now, convert to improper fractions.
1
![\frac{3}{100} = [tex] \frac{103}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B100%7D%20%20%3D%20%5Btex%5D%20%5Cfrac%7B103%7D%7B100%7D%20)
-10

=

Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
