1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
REY [17]
3 years ago
13

Two candidates are running for mayor in a small town. The campaign committee for candidate A has been conducting weekly telephon

e polls to assess the progress of the campaign. Currently, there are 16,000 registered voters, 43% of whom are planning to vote. Of those planning to vote, 59% will vote for candidate A. Candidate B has begun some serious mudslinging, which has resulted in increasing public interest in the election and decreasing support for candidate A. Polls show that the percentage of people who plan to vote is increasing by 5 percentage points per week, and the percentage who will vote for candidate A is declining by 4 percentage points per week. How rapidly is the number of votes that candidate A will receive increasing at this moment? (Answer in the nearest integer.)
Mathematics
1 answer:
lakkis [162]3 years ago
3 0

Answer:

a) 6,880

b) 4,059

c) Check Explanation

The number of expected votes for candidate A increases only in the first 3 weeks of mudslinging. The rate of weekly increase in those 3 weeks, is provided in the explanation. The number changes weekly for those 3 weeks with an average increase of 101 new votes per week.

Step-by-step explanation:

a. If the election were held today, how many people would vote?

b. How many of those would vote for candidate A?

c. How rapidly is the number of votes that candidate A will receive increasing at the moment?

There are 16,000 registered voters, 43% of whom are planning to vote, with 59% planning to vote for candidate A.

a) Number of registered voters planning to vote = 43% × 16000 = 6880

b) Number of registered voters that will vote and vote for candidate A

= 59% of registered voters planning to vote

= 59% × 6880 = 4059.2 ≈ 4059 people

c) Polls show that the percentage of people who plan to vote is increasing by 5 percentage points per week, and the percentage who will vote for candidate A is declining by 4 percentage points per week.

Since, the 'moment' isn't specified, we will check how much the number is increasing for the first 4 weeks after the mudslinging by candidate B began

Normally, 43% of registered voters want to vote, but now it is increasing at a rate of 5% per week. So, the percentage of registered voters that want to vote is now

43% + 5x% (where x = number of weeks after the mudslinging by candidate B started)

And the percentage of voting, registered voters that want to vote for candidate A is now (59% - 4x%)

After a week, percentage of registered voters that will vote = 48%

Number of registered voters that will vote = 48% × 16000 = 7680

percentage of voting, registered voters that want to vote for candidate A = 55%

Number of voting, registered voters that want to vote for candidate A = 55% × 7680 = 4224

Difference between the initial number of expected votes for candidate A between the beginning of the mudslinging and end of week 1

= 4224 - 4059 = 165

After week 2,

percentage of registered voters that will vote = 53%

Number of registered voters that will vote = 53% × 16000 = 8480

percentage of voting, registered voters that want to vote for candidate A = 51%

Number of voting, registered voters that want to vote for candidate A = 51% × 8480 = 4324.8 = 4325

Difference between the number of expected votes for candidate A between week 1 and week 2

= 4325 - 4224 = 101

After week 3,

percentage of registered voters that will vote = 58%

Number of registered voters that will vote = 58% × 16000 = 9280

percentage of voting, registered voters that want to vote for candidate A = 47%

Number of voting, registered voters that want to vote for candidate A = 47% × 9280 = 4361.6 = 4362

Difference between the number of expected votes for candidate A between week 2 and week 3

= 4362 - 4325 = 37

After week 4,

percentage of registered voters that will vote = 63%

Number of registered voters that will vote = 63% × 16000 = 10,080

percentage of voting, registered voters that want to vote for candidate A = 43%

Number of voting, registered voters that want to vote for candidate A = 43% × 10080 = 4334

Difference between the number of expected votes for candidate A between week 3 and week 4

= 4334 - 4362 = -28

The number of expected votes for candidate A begins to decline after the 4th week of mudslinging.

So, the required 'moment' should be within the first 3 weeks of mudslinging. And the rate of increase weekly is provided above with an average increase of 101 new voters per week.

Hope this Helps!!!

You might be interested in
The diagonal of the rectangle is 10 inches long and the height of the rectangle is 8 inches. What is the perimeter of the rectan
hoa [83]

Basic perimeter is really easy to understand;

Step-by-step explanation:

10 x 8 = 80 in.

80 in. is your answer! Please mark brainliest and have a great day! :D

6 0
3 years ago
Which number is the additive inverse of -4 1/4
vovangra [49]
The additive inverse of a number is the opposite number......for this problem, it is a number, that when added to -4 1/4 = 0.

so the additive inverse of -4 1/4 = 4 1/4
8 0
3 years ago
Read 2 more answers
I'm only good at answering not solving:,)
Mazyrski [523]

Answer:

1/3 chance for even 1/3 chance for odd

7 0
3 years ago
Read 2 more answers
in which place is the digit in the numbers 5,341 that would be changed to form 5,841? how do the values of the two numbers compa
Akimi4 [234]

The changed digit is the third to the left of the decimal point, so is in the hundreds place.

The value of 8 hundred is 5 hundred more than the value of 3 hundred. The second number is 500 more than the first.

7 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
ELEN [110]

Answer:

Volume~of~cylinder=\pi r^2h

  • \pi *(10)^2*5
  • 500\pi
  • 1570.8~m^3

<u>-------------------------</u>

<u>hope it helps..</u>

<u>have a great day!!</u>

3 0
3 years ago
Read 2 more answers
Other questions:
  • Leota is having some friends over and is buying some drinks. She buys a 10 pack of canned soda for $3.00.
    14·1 answer
  • 22. The tangent of an angle is 7.5. What is the measure of the angle to the nearest tenth?
    10·2 answers
  • is (3,-3) a solution to the system 5x+4y=3, 2x-5y=19 need to be taught step by step please and thank you.
    9·2 answers
  • What is the value of the expression - x [ 6 + ( 4 x 2 ) ] - 5
    5·1 answer
  • A right triangle contains a 38° angle whose adjacent side measures 10 centimeters. What is the length of the hypotenuse, to the
    13·1 answer
  • What do we put in the first boxes
    5·1 answer
  • What decimal does the model represent?
    9·2 answers
  • What is the value of x in the equation below?<br><br> 4x + 6 = 18
    15·2 answers
  • A reasonable estimate for 621 times 29 is
    13·1 answer
  • Convert the following repeating decimals to
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!