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Vikentia [17]
2 years ago
5

10x+2=9x3 what is the answer

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
6 0

Answer:

8.5

Step-by-step explanation:

10x+2=9x(3)

10x+2=27x

2=17x

x=8.5

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What is the solution to w-11=1.3
trapecia [35]
<span>Simplifying w + -11 = 1.3
 
Reorder the terms: -11 + w = 1.3
 
Solving -11 + w = 1.3
 
Solving for variable 'w'. Move all terms containing w to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + w = 1.3 + 11
 
Combine like terms: -11 + 11 = 0 0 + w = 1.3 + 11 w = 1.3 + 11
 
Combine like terms: 1.3 + 11 = 12.3 w = 12.3
 
Simplifying w = 12.3 <--- (Answer)

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The formula for centripetal acceleration, a, is given below, where v is the velocity of the object and r is the object's distanc
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Step-by-step explanation:

For this case we have the following equation:

a = v ^ 2 / r

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3 0
2 years ago
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For the following right triangle, find the side length x.​
never [62]

Answer:

x = 10

Explanation:

Using Pythagoras Theorem:

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8² + 6² = x²

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I need help please will give you 5 stars and good rating
Brums [2.3K]

Answer:

Step-by-step explanation:

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3 years ago
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what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
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