Answer:

Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have

and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
and by evaluating in the limits we have

Hope this helps
regards
Answer:
x=50
Step-by-step explanation:
(x-10)+x+90=180
2x-10+90=180
2x+80=180
2x=100
<u><em>x=50</em></u>
Answer:
Coordinates: (2, -1)
Part A
X coordinate is positive
Y coordinate is negative
Part B
Coordinates after Y-axis reflection: (-2, -1)
X coordiate is negative
Y coordinate is negative
Good luck!
For this case we have the following function:

By definition, we have that a linear equation is of the form 
On the other hand, a quadratic equation is of the form
Then, the given equation is not a linear equation, it is not of the form 
Answer:
No, the equation is not linear. It is not of the form 