name the property /properties that is displayed in each of the (A)1+3=3+1 . (B)2x(3×4)=(2×3)+(2×4). C (2+3)×5=(5×3)+(5×2)

1 answer:

8 0

A) commutative property of addition (because the order is switched)

B) distributive property (2 is multiplied to 3 and 4)

C) distributive property (5 is multiplied to 3 and 2)

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2x+3y=15<br> X+y=6<br> Simultaneously equations

Lerok [7]

Answer:

Step-by-step explanation:

Let's solve your system by substitution.

2x+3y=15;x+y=6

Rewrite equations:

x+y=6;2x+3y=15

Step: Solvex+y=6for x:

x+y=6

x+y+−y=6+−y(Add -y to both sides)

x=−y+6

Step: Substitute−y+6forxin2x+3y=15:

2x+3y=15

2(−y+6)+3y=15

y+12=15(Simplify both sides of the equation)

y+12+−12=15+−12(Add -12 to both sides)

y=3

Step: Substitute3foryinx=−y+6:

x=−y+6

x=−3+6

x=3(Simplify both sides of the equation)

Answer:

x=3 and y=3

7 0

3 years ago

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WITCHER [35]

Answer:

Area = 15.36 ft

Step-by-step explanation:

First find the area of the dotted line triangle using the formula: base x height x 1/2, which would be 1.2ft x 12.8 x 1/2 = 7.68ft.

Next, add another triangle at the top, mirroring the shown triangle, of the parallelogram.

Then, find the area of the shape as though it were a rectangle. (base x height) - 2.4 x 12.8 = 30.72.

Next, multiply the area of the invisible triangle by 2, 7.68 x 2 = 15.36ft

and Finally, subtract the area of the rectangle shape of the the sum of the two invisible triangles, 30.72 - 15.36 = 15.36ft

The area of the parallelogram is 15.36 ft.

5 0

3 years ago

Use the divergence theorem to calculate the surface integral ??s f · ds; that is, calculate the flux of f across s. f(x,y,z = ex

Kamila [148]

$\mathbf f(x,y,z)=e^x\sin y\,\mathbf i+e^x\cos y\,\mathbf j+yz^2\,\mathbf k$

By the divergence theorem, the surface integral can be evaluated by computing the triple integral

$\displaystyle\iint_Sf(x,y,z)\,\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$
$=\displaystyle\iiint_V\left(\dfrac{\mathrm d\mathbf f}{\mathrm dx}+\dfrac{\mathrm d\mathbf f}{\mathrm dy}+\dfrac{\mathrm d\mathbf f}{\mathrm dz}\right)\,\mathrm dV$
$=\displaystyle\int_{x=0}^{x=4}\int_{y=0}^{y=3}\int_{z=0}^{z=4}2yz\,\mathrm dz\,\mathrm dy\,\mathrm dx$
$=72$